The ratio of the angle of minimum deviation produced by a thin prism $(\mu = 3/2)$ in air to that in a liquid of refractive index $9/7$ is:

$A$ ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence,and each of these angles is equal to $\left(\frac{3}{4}\right)^{th}$ of the angle of the prism. The angle of deviation is: (in $^{\circ}$)

In the diagram,a ray is passing through a broken prism. Find the angular deviation for the ray. (in $^{\circ}$)

$A$ spectrum is formed by a prism of dispersive power $\omega$. If the angle of deviation is $\delta$,then the angular dispersion is

The refracting angle of a prism is $A$ and the refractive index of the material of the prism is $\cot (A / 2)$. The angle of minimum deviation of the prism is

The refractive index $(R.I.)$ of a prism is $\sqrt{\frac{7}{3}}$ and the angle of the prism is $60^{\circ}$. The limiting angle of incidence of a ray that will be transmitted through the prism is .....$^{\circ}$